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-15x^2-15x+25=0
a = -15; b = -15; c = +25;
Δ = b2-4ac
Δ = -152-4·(-15)·25
Δ = 1725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1725}=\sqrt{25*69}=\sqrt{25}*\sqrt{69}=5\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{69}}{2*-15}=\frac{15-5\sqrt{69}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{69}}{2*-15}=\frac{15+5\sqrt{69}}{-30} $
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